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13C NMR Problems
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Problem 10 Solution

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Spectrum A is for 3-bromotoluene.

Spectrum B is for the benzoate.

Both molecules are expected to show 7 peaks; however, spectrum B has a peak at 168 ppm due to the carbonyl carbon of the ester group.

In spectrum A, the methyl group of bromotoluene is obvious at 22 ppm; the remaining peaks are all in the aromatic region.

In spectrum B, the carbon atoms of the two OCH3 groups can be seen at 52 ppm and 56 ppm.

Last Updated: 10/07/2014
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