Chemistry 142

George fall’08

Lec Quiz - Acid/base buffers                                                name

 

SHOW ALL WORK FOR CREDIT

 

 

 

1. (20pts)  Solution A is prepared by dissolving 32.0 g of solid NH4NO3 (80.0 g/mole) in 500 mL of 0.50 M NH3. (Assume the solution volume is still 500 mL.)

 

(a)    SHOW ALL WORK. Determine the pH of solution A.

      Straight equilibrium_

 

NH4+(aq)  +    H2O(l)  ίΰ    NH3(aq)  +    H3O+(aq)

I (mol)  0.40                 ~ 0              0.25             ~0

                       - x                  --           +x                + x

            E           0.40-x             --              0.25 + x     x

 

            (0.25 + x)(x)  = 10-14               approx x to “0” and solve

            0.40 –x               1.8 x 10-5    

 

            X = 8.9 x 10-10  and pH = 9.0 (1 sig fig)

 

 

 

(b)    SHOW ALL WORK. Suppose that 100 mL of 2.50 M NaOH is added to Solution A. Determine the pH of the resulting solution.

 

1st  do the chemistry that goes to completion

                        OH-(aq)  +  NH4+(aq) ΰ  HOH(l)    +  NH3(aq)

Mol before rxn          0.25             0.40                                       0.25

Mol used rxn           -0.25           -0.25                                       +0.25

Mol after rxn              “0”              0.15                                        0.50

 

            2nd now for the equilibrium

                       

                        NH3(aq)   +  HOH(l) ί ΰ   NH4+(aq)  +  OH-(aq)

                   I      0.50           --                   0.15           “0”

 

                   Δ       -x             --                     +x              +x

 

                   E     0.50 – x                             o.15 +x       +x   

 

            Now plug into Kb for NH3  and approximate x to zero-

           

            (0.15 mol NH4+/0.60L)(x)   = 1.8 x  10-5, giving x = 6.0 x 10-5, and pH = 9.8

              (0.50 mol NH3/0.60L)   

            Note_the volumes cancel and there is 1 sf         

(c)     SHOW ALL WORK. Suppose instead that 100 mL of 2.50 M HNO3 is added to Solution A. Determine the pH of the resulting solution.

 

 

            1st  do the chemistry that goes to completion

 

                        H+(aq)  +  NH3(aq) ΰ  HOH(l)    +  NH4+(aq)

Mol before rxn          0.25             0.25              --                     0.40

Mol used rxn           -0.25           -0.25                                     +0.25

Mol after rxn              “0”               “0”                                       0.65

 

 

2nd now for the equilibrium

                       

NH4+(aq)  +    H2O(l)  ίΰ    NH3(aq)  +    H3O+(aq)

 

                   I      0.65           --                      “0”                “0”

 

                   Δ       -x             --                      +x                    +x

 

                   E     0.65 – x                              +x       +x   

 

 

Use Ka  which is Kw/ Kb  =  1.0 x 10-14    =   x2

                                              1.8 x 10-5         (0.65/ mol/0.60L)

 

-logx  = pH = 4.6