Chemistry 142
George fall08
Lec Quiz -
Acid/base buffers
name
SHOW ALL WORK
FOR CREDIT
1. (20pts)
Solution A is prepared by dissolving 32.0 g of solid NH4NO3
(80.0 g/mole) in 500 mL of 0.50 M NH3. (Assume the solution volume
is still 500 mL.)
(a)
SHOW ALL WORK. Determine the
pH of solution A.
Straight equilibrium_
NH4+(aq) + H2O(l) ίΰ NH3(aq) + H3O+(aq)
I (mol) 0.40 ~ 0 0.25 ~0
∆ - x -- +x + x
E 0.40-x -- 0.25 + x x
(0.25 + x)(x) = 10-14 approx x to 0 and solve
0.40 x 1.8 x 10-5
X = 8.9 x 10-10 and pH = 9.0 (1 sig fig)
(b)
SHOW ALL WORK. Suppose that
100 mL of 2.50 M NaOH is added to Solution A. Determine the pH of the
resulting solution.
1st do the chemistry that
goes to completion
Mol before rxn 0.25 0.40 0.25
Mol used rxn -0.25 -0.25 +0.25
Mol after rxn 0 0.15 0.50
2nd now for the equilibrium
NH3(aq)
+ HOH(l) ί ΰ NH4+(aq) +
I
0.50 -- 0.15 0
Δ -x -- +x +x
E 0.50 x o.15 +x +x
Now plug
into Kb for NH3 and approximate x to zero-
(0.15 mol NH4+/0.60L)(x) =
1.8 x 10-5,
giving x = 6.0 x 10-5, and pH = 9.8
(0.50 mol NH3/0.60L)
Note_the volumes cancel and
there is 1 sf
(c)
SHOW ALL WORK. Suppose
instead that 100 mL of 2.50 M HNO3 is added to Solution A. Determine
the pH of the resulting solution.
1st do the chemistry that goes to completion
H+(aq) + NH3(aq)
ΰ HOH(l) + NH4+(aq)
Mol before rxn
0.25 0.25 -- 0.40
Mol used rxn -0.25 -0.25 +0.25
Mol after rxn 0 0 0.65
2nd now for
the equilibrium
NH4+(aq) + H2O(l) ίΰ NH3(aq) + H3O+(aq)
I
0.65 -- 0 0
Δ -x -- +x
+x
E 0.65 x +x +x
Use Ka which is Kw/
Kb = 1.0 x 10-14 = x2
1.8 x 10-5 (0.65/ mol/0.60L)
-logx = pH = 4.6