EXPERIMENT 6
Limiting Reagent
PRELAB NOTES
Example:
If moles
KIO3 = .01402
and if
moles Pb(NO3)2 = .009063
then the
mole ratio ![]()
Example:
Suppose
the theoretical mole ratio is ![]()
then the
actual mol ratio of 1.547 is too low, which means that the numerator of the
ratio, namely Òmol KIO3Ó is too low, and so KIO3 is the
limiting reagent.
Name
Section
Date
PRELABORATORY EXERCISE
LIMITING REAGENT
Read the prelab notes and the
experiment, then complete the following as directed.
_______
Pb(NO3)2 + _______ KIO3 ¨
_______ Pb(IO3)2 + _______ KNO3

Name
Section
EXPERIMENT 6
LIMITING REAGENT STOICHIOMETRY
Purpose: The
purpose of this experiment is to deal with the concept of limiting reactant in
a chemical equation.
Theory: When
two or more reactants react chemically they do so in a certain mole ratio (the
stoichiometric ratio). This can be seen from the equation:
2NaOH + H2SO4 ¨
Na2SO4 + 2H2O
where two moles of sodium hydroxide
react with one mole of sulfuric acid (forming one mole of sodium sulfate and
two moles of water).
If one of the reactants is present in
an amount less than the stoichiometric proportion to that of the other (or
those of the others), it will limit the amount of products produced. Thus, if
two moles of sodium hydroxide and one-half mole of sulfuric acid are allowed to
react, only one mole of the sodium hydroxide will be consumed with the half
mole of acid, and only one-half mole of sodium sulfate and one mole of water
will be produced. In this example, the sodium hydroxide is said to be present
in excess, and sulfuric acid is called the limiting reactant (or limiting
reagent).
Method: For this
experiment you will work with the metathetical reaction between lead (II)
nitrate and potassium iodate, which produces insoluble lead (II) iodate. From
the balanced reaction equation you will determine the correct stoichiometric
ratio of reactants. You will then combine different weights of reactants,
collect and weigh the insoluble product, and compare the results to those
predicted by the equation.
Caution: Remember that
lead salts are extremely toxic.
Procedure: A letter,
corresponding to a certain amount of each of the two reactants, will be
assigned to you. Obtain from the reagent shelf—in separate 50 ml
beakers—quantities of those reagents approximating the values assigned.
(Sample sizes will be on display on the instructorÕs desk.) Weigh out the
proper amounts to the nearest milligram. Try to get with +/- .050 grams of your
assigned quantity. Remember it is more important to know exactly how much of
each reactant you have than to get exactly the amount assigned. Do this by
transferring reagent with your spatula from your beaker to a piece of
pre-weighed (or tared) weighing paper, until the amount is reached. Then, for
each reagent, carefully transfer the weighed amount from the weighing paper to
a separate, properly labeled, 250-ml beaker. Make sure all of each reagent is
transferred to its respective beaker. To each 250-ml beaker add 100 ml of D1
water and dissolve both reagents.
With a stirring rod, gently pour and
mix the lead (II) nitrate solution into the potassium iodate solution. Rinse the
beaker with DI water to assure a quantitative transfer of lead (II) nitrate.
While gently stirring the mixture, heat it up until it is almost to the boiling
point, then let it settle and cool for about ten minutes. While this is cooling
set up a BŸchner funnel and vacuum train. The equipment may be checked out from
the stockroom and the set-up will be demonstrated by the instructor.
Weigh a piece of fiberglass 7.5 cm
filter paper to the nearest milligram and record the weight. Place the filter
paper into the BŸchner funnel and dampen it to make it stick. Slowly turn on
the vacuum line. (Too great a vacuum will cause the paper to tear.) Pour the
contents of the beaker into the funnel so that the suspended precipitate goes
onto the center part of the filter. If you can keep the precipitate back from
the edge, it will be much easier to remove the filter paper, dry it and weigh
it without loss of any solid. Remove the remaining precipitate from the beaker
by using three 25 ml portions of water and your rubber policeman to scrub the
solid Pb(IO3)2 from the sides of the beaker. Allow the
suction to dry the precipitate for a minute or so; then turn off the vacuum and
carefully remove the filter paper and precipitate, losing as little as
possible. Dry the paper and reaction product on a labeled watch glass for 30
minutes in an oven set at 110¡C.
Weigh the cooled filter paper, watch
glass and precipitate to the nearest milligram and record. If at all possible,
reheat your filter paper and precipitate for another 30 minutes. Cool and
reweigh. The second weighing should agree with the first one to within .004 g.
Calculations: Determine the expected weight of product from the reaction
equation and your actual initial weights. Compare the expected weight
with your result and calculate your percent yield.
Name
Section
Date
EXPERIMENT
6
LIMITING
REAGENT STOICHIOMETRY
REPORT
SHEET
DATA Assigned
Letter
Pb(NO3)2 Calculated
moles to use
KIO3 Calculated
moles to use
Actual weight of Pb(NO3)2
used.
mass
Pb(NO3)2 + weighing paper =
Actual moles Pb(NO3)2
used
mass
weighing paper =
mass
Pb(NO3)2 =
Actual weight of KIO3 used.
mass
KIO3 + weighing paper =
Actual moles KIO3 used:
mass
weighing paper =
mass
KIO3 =
Weight
of filter paper g
Weight
of watch glass g
Weight
of filter paper, watch glass g
and
precipitate 1st drying
Weight
of filter paper, watch glass g
and
precipitate 2nd drying
RESULTS
Reagent
present in excess Limiting reactant
(based
on actual weights used)
Expected
number of moles of Pb(103)2
Expected
weight of PB(103)2
g
Actual
weight of Pb(103)2 collected
g
Percent
Yield
LIMITING REACTANT
STOICHIOMETRY
Problems
The following four questions are based
on the reaction
2
KC1 + 2 MnCl2 + 5 PbO2 + 4 HC1 ¨ 2
KMnO4 + 5 PbC12 + 2H2O
in which 25.00 g of MnC12 is
reacted with 100.0 g of PbO2.